Temple of Kraden News:
| Greetings, heathen. Perhaps some fortuitous blessing of Kraden's grace hath led you to our humble Temple, or perhaps you are simply curious about this strange and wonderful cult. Should you be willing - and dare to hope - to achieve enlightenment, the door opens before you. Lo! Leave your old life behind! For once you step through, you become something more than just yourself. You become a Kradenette. Are you willing to make the rapturous plunge? Do you have what it takes? One of us! One of us! One of us! Already one of us? Make your presence known: |
| Mathematical proof of my awesomeness. | |
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| Tweet Topic Started: Mar 26 2009, 08:40 PM (774 Views) | |
| Chrono Ivan | Mar 26 2009, 08:40 PM Post #1 |
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He who strikes like lightning
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1/0 *Doesn't explode* |
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| Mia | Mar 26 2009, 08:59 PM Post #2 |
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I'M NOT INNOCENT!
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Speaking of proof... I hate trigonometry identities. Second semester of Pre-Cal is terrible. 1. Simplify: sin^2 x cot^2 x sec x+ sin^2 x Remember to keep the identities in terms of sine and cosine. First step: Sin^2 x (cos^2 x/sin ^2 x) (1/cos x) + sin^2 x Second step: (cancel out similar terms) What you have left is cos x +sin^2 x 2. Simplify: tan x cos x First step: (sin x/cos x) cos x Second step: (sin x/ cos x) (cos x/1) Third step: (cancel similar terms) Final answer is sin x 3. Proof: cos x+ sin x tan x= sec x First step: cos x+ [sin x (sin x/cos x)] Second step: Multiply the trig identities in the bracket. Cos x+ (sin x^2/cos x) Third step: cos x/1+ (sin x^2/cos x) Fourth step: Find common denominator. Multiply numerator and denominator. (Cos x) Cos x + Sin^2 x = Cos^2 x + sin^2 x (cos x) 1 cos x cos x cos x Fifth step: Check the Pythagorean Identities. Cos^2 x + Sin^2 x = 1 Cos x ( cos x) Sixth step: Check the reciprocal identities 1/(cos x)= sec x 4. Proof: cos x/(1-sin x) = sec x+ tan x First step: Rationalize cos x/(1-sin x) cos x/(1-sin x) (1+sin x)/(1+sin x) The sign changed because I had to rationalize and reciprocal the denominator. Second step: Multiply the equation cos x/(1-sin x) (1+sin x)/(1+sin x) The answer should be [cos x (1+sin x)]/( 1-sin^2 x) Third step: Use Pythagorean Identities. The next set up should be: [cos x (1+sin x)]/ (cos^2 x) Fourth step: Cancel out cos x. The next set up should be: (1+sin x) /cos x Fifth step: Split up the denominator and it should look like this: 1/cos x+ sin x/cos x Sixth step: Use reciprocal identities and quotient identities to verify the right side of the original equation. 1/cos x+ sin x/cos x= secx+ tan x 5. Proof: sec^2 x/ tan x= sec x csc x First step: sec^2 x become 1/cos^2 x based on the reciprocal identities The set up of the problem should be (1/cos^2 x) / tan x Second step: Use quotient identity to change tan x to sin x/ cos x (1/cos^2 x) / (sin x/ cos x) Third step: Reciprocal (1/cos^2 x) (cos x/ sin x) Fourth step: Cancel out cos x After canceling it, the problem should be: (1/cos x)(1/sin x) Fifth step: Check reciprocal identities to prove that (1/cos x)(1/sin x)= sec x csc x |
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| Kris, Awooer of Worlds | Mar 26 2009, 09:01 PM Post #3 |
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Awoo!
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Mia, are you in /Pre-/AP Pre-cal? 'Cause I don't recall that stuff. |
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| Mia | Mar 26 2009, 09:06 PM Post #4 |
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I'M NOT INNOCENT!
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Yeah. |
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| Kris, Awooer of Worlds | Mar 26 2009, 09:11 PM Post #5 |
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Awoo!
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Makes sense. XD |
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| Chrono Ivan | Mar 27 2009, 01:50 PM Post #6 |
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He who strikes like lightning
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You call THIS spamming? Arg. Needs moar something. |
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| Elephande | Mar 27 2009, 03:41 PM Post #7 |
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Hiata Zealo, Salvis Frontain
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![]() I comply. |
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| The Phantom Squee | Mar 27 2009, 05:02 PM Post #8 |
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Sound the horn and call the cry: "How many of them can we make die?"
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Linked for spoiler |
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| Shiroi Jigoku | Mar 29 2009, 04:04 AM Post #9 |
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Elemental
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... WAT? |
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| Lachesis | Mar 29 2009, 07:52 AM Post #10 |
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What are birds?
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Just a little bit of a spoiler there, Squee. |
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| The Phantom Squee | Mar 29 2009, 04:51 PM Post #11 |
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Sound the horn and call the cry: "How many of them can we make die?"
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Oh, really? I haven't seen the show, so I didn't know. I'll link it. |
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| Spella | Mar 29 2009, 05:17 PM Post #12 |
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Krissy's Queen of the Lilies
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wtftopic. |
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| Enro | Mar 30 2009, 06:03 AM Post #13 |
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Sol Aurarius
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What till uni, Mia. Vector line integrals, lawl. *Head asplodes* |
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